Answer:
Marcos had 6 nickel coins and 9 quarter coins.
Step-by-step explanation:
We are given the following in the question:
Let x be the number of nickel coins and y be the number of quarter coins.
Marcos had 15 coins in nickels and quarters.
Thus, we can write the equation:
[tex]x + y =15[/tex]
He had 3 more quarters than nickels. We can write he equation,
[tex]y = x + 3[/tex]
Solving the two equations, we get,
[tex]2y = 18\\y = 9\\x + 9 = 15\\x = 6[/tex]
Thus, Marcos had 6 nickel coins and 9 quarter coins.
