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The total energy of a 0.050 kg object travelling at 0.70 c is

A) 2.10 × 107 J

B) 3.06 × 107 J

C) 2.46 × 1015 J

D) 6.30 × 1015 J

E) 8.82 × 1015 J

Respuesta :

olemakpadu
Would presume the energy as kinetic energy.

E = (1/2)*mv²

But m = 0.05kg, velocity here = 0.70c, where c is the speed of light ≈ 3* 10⁸ m/s

Ke =  (1/2)*mv² = 0.5*0.05*(0.7*3* 10⁸)² = 1.1025 * 10¹⁵ Joules


There is no exact match from the options.

Answer:

6.33x10^15

Explanation:

Im sure its too late but this might help someone in the future

the right formula to use is

Etotal=(mc^2)/sqr(1-v^2/c^2)