Answer:
[tex]h(t)=68t+12[/tex]
Step-by-step explanation:
let t= time in seconds, h=height in ft
height at [tex]t_0=12ft[/tex]=[tex]h_o[/tex]
Velocity,v=[tex]68m/s[/tex]
Height=[tex]velocity*time=vt[/tex]
[tex]h_t=h_0+h_(t-0)[/tex]
Therefore height after [tex]t_n[/tex] is obtained by adding height gained to initial height.
[tex]h(t)=68t+12[/tex]