Answer:
367.64 meters
Step-by-step explanation:
Using the kinetic equation where:
Vf ^ 2 - Vi ^ 2 = 2ax
We know that:
Vf = 0 m / s
Vi = 50 m / s
The acceleration can be calculated by means of F = M.a
F = -8500 (because it is stopping, braking force) and m = 2500 kg
We have left that a = F / M = -8500/2500 = -3.4 m / s ^ 2
Now reorganizing we have that:
x = -Vi ^ 2 / 2a
replacing the values is:
x = - (50 ^ 2) / (2 * -3.4) = 367.64 meters and this would be the distance the car travels when it stops.
