Respuesta :
Answer:
7boxes
Step-by-step explanation:
A box can hold a maximum of 8 cans
You have a total of 50 cans
The problem here is to determine the minimum number of boxes that can hold the 50 cans
Let the minimum number of boxes = y
The minimum required will be such that:
The Product of The number of cans X Number of Required boxes ≥50
8y≥50
y≥50/8
y≥6.25
Since a box have a fractional value, the minimum number of boxes required to store 50 cans will be the nearest whole number which in this case is 7.
Using proportions, it is found that the smallest number of boxes you need to store all of the cans in boxes is of 7.
- This question is solved by proportions, applying a rule of three.
- One box holds 8 cans. How many boxes are needed to hold 50 cans?
The rule of three is:
1 box - 8 cans
x boxes - 50 cans
Applying cross multiplication:
[tex]8x = 50[/tex]
[tex]x = \frac{50}{8}[/tex]
[tex]x = 6.25[/tex]
Rounding up, 7 boxes are needed.
You can learn more about proportions at https://brainly.com/question/24372153
