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Write programs that read a sequence of integer inputs and print a. The smallest and largest of the inputs. b. The number of even and odd inputs. c. Cumulative totals. For example, if the input is 1 7 2 9, the program should print 1 8 10 19. d. All adjacent duplicates. For example, if the input is 1 3 3 4 5 5 6 6 2, the program should print 3 5 6.

Respuesta :

ammary456

Answer:

def find(lst):

   max = lst[0]

   min = lst[0]

 

   total_even = 0

   total_odd = 0

   for x in lst:

       if(max < x):

           max = x

       if(min > x):

           min = x

       if(x%2 == 0):

           total_even += 1

       else:

           total_odd += 1

   print("Maximum = ", max)

   print("Minimum = ", min)

   print("total even =", total_even)

   print("total odd =", total_odd)

   print("total: ",end="")

   temp = 0

   for x in lst:

       temp += x

       print(temp, end=" ")

   pre = lst[0]

   i = 1

   print("\n Close duplicates: ",end="")

   while i<len(lst):

       flag = False

       while(pre == lst[i] and i<len(lst)):

           pre = lst[i]

           i += 1

           flag = True

       if(flag):

           print(pre,end=" ")

       pre = lst[i]

       i += 1

   print("\n\n\n")

find([1, 3, 3, 4, 5, 5, 6, 6, 6, 2])

find([1, 7, 2, 9])

Explanation:

  • Check if a number is even or odd by taking a mod with 2.
  • Display all the counts of even, odd, maximum, minimum numbers.
  • Run a while loop until pre == lst[i] and i<len(lst) and mark the flag as True.
  • Call the find function.
fichoh

The python 3 program written below performs all the stated functions required in the question :

t = input('Enter values : ')

#takes inputs from user

mylist = [int(x) for x in t.split()]

#reads the inputs into a list

cum_total =0

total = []

even = 0

odd = 0

#initialize containers to hold our variables

print(min(mylist), max(mylist))

#displays the minimum and maximum values in the list.

for num in mylist:

#iterate through the values in the list

cum_total+=num

#takes the Cummulative sum

total.append(cum_total)

#append to the list

if num%2 == 0:

#checks for even values

even+=1

#increases count by 1

else:

odd+=1

print('number of even', even)

print()

print('number of odd', odd)

print()

print(total)

#displays the values required.

Learn more : https://brainly.com/question/25103873

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