Respuesta :
Answer:
a) 0.6
b) 0.4
Explanation:
The number of states available in macrostate 1 = 1 basic state
The number of states in macrostate 3 = 1 basic state too
But the number of states of macrostate 2 = 3 × (number of states in either of the macrostate 1 or 3) = 3 × 1 = 3
Total number of states available in the macrostates = 1+3+1 = 5
a) probability that the equilibrium state 2 occurs = (number of states available in equilibrium 2)/(total number of states) = (3/5) = 0.60
b) probability that microstate 1 or 3 occurs = (number of states available in microstate 1 or 3)/(total number of states) = 2/5 = 0.4
A) The probability that the equilibrium state 2 occurs is; 0.6
B) The probability that microstate 1 or 3 occurs is;
0.4
We are given;
- Number of states available in Macrostate 1 = 1 basic state
- Number of states in Macrostate 3 = 1 basic state
Now, Microstate 2 is 3 times more likely to occur than either of Microstate 3 or 1.
Thus;
Number of states in Macrostate 2 is;
3 × 1 = 3
Total number of states available in Macrostates 1, 2 and 3;
1 + 3 + 1 = 5
A) Probability that the equilibrium state 2 occurs is;
P(eq 2 occurs) = (number of states available in equilibrium 2)/(total number of states)
P(eq 2 occurs) = (3/5) = 0.6
B) Probability that microstate 1 or 3 occurs is;
P(eq 1 or 3 Occurs) = (Number of states available in microstate 1 or 3)/(total number of states)
P(eq 1 or 3 Occurs) = 2/5 = 0.4
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