Answer:
5.72 s
Explanation:
From Newton's law, F = ma
The East is +ve direction, Hence,
F = +8930 N
m = 2290 kg
a = ?
8930 = 2290 × a
a = 8930/2290 = 3.90 m/s²
So, we will find the time it takes the car to stop using the equations of motion
a = 3.90 m/s²
u = initial velocity of the car = - 22.3 m/s (the velocity is to the west)
v = final velocity of the car = 0 m/s (since the car comes to rest)
t = time taken for the car to come to rest = ?
v = u + at
0 = - 22.3 + (3.90)(t)
3.9t = 22.3
t = 5.72 s
Answer:
5.72 s.
Explanation:
F = 8930 N
M = 2290 kg
u = 22.3 m/s
Note, F = M × a
a = 8930 ÷ 2290
= 3.9 m/s^2
Using equation of motion,
v = u + at
22.3 = 3.9t
t = 5.72 s.
