Answer:
1a.) 0.4918
1b.) 0.5082
2a.) 1
2b.) 0.56
2c.) 0.70
Step-by-step explanation:
probability that death was caused by a heart disease = p(H) = 0.34
probability that death was caused by cancer p(C)= 0.23
For question 1a,
Probability that death was caused by either heart disease or cancer = p(H) + p(C) - [p(H) * p(C)
= 0.34 + 0.23 - (0.34*0.23)
= 0.57 - 0.0782
= 0.4918.
1b.) Probability that death was caused by other cause = 1 - [probability that death was caused by heart failure or cancer
= 1 - 0.4918
= 0.5082
For question 2,
a.) Sum of all the probabilities = 0.44 + 0.26 + 0.23 + 0.06 + 0.01 = 1
The sum is 1 because the Sum of the probabilities of all outcomes of an event must be equal to 1.
b.) Probability that a randomly chosen first year student was NOT part of top 20% = 1 - [probability that. Randomly chosen first year student was in top 20%]
= 1 - 0.44
= 0.56
C.) probability that Student was in top 40% = 0.44 + 0.26
=0.70