A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and vertical components of the skier's displacement? (Use trigonometry to solve.)

Respuesta :

d=235m

Alpha=35⁰

h=d×sin(alpha)=134.8m

L=d×cos(alpha)=192.5m

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