Answer:
a) Q
Explanation:
- If the capacitors are connected in series, across a potential source (battery) , the battery voltage is divided between the capacitors, as follows:
[tex]V = V_{1} + V_{2} +V_{3}[/tex]
- By definition, each voltage is related with the capacitance and the charge, as follows:
[tex]V = V_{1} + V_{2} +V_{3} = \frac{Q_{1} }{C_{1}} + \frac{Q_{2} }{C_{2}} + \frac{Q_{3} }{C_{3}}[/tex]
- Now, due to the principle of conservation of charge, this can't neither accumulate nor dissapear at any point in the circuit, so the charge must be the same for each capacitor:
[tex]Q = Q_{1} = Q_{2} = Q_{3}[/tex]
