Respuesta :
Answer:
The ppm carbon in the seawater is 104.01.
Explanation:
Mass of seawater = 6.234 g
Mass of carbon dioxide gas produced = 2.378 mg = 0.002378 g
1 mg = 0.001 g
Moles of carbon dioxide gas = [tex]\frac{0.002378 g}{44.009 g/mol}=5.4034\times 10^{-5} mol[/tex]
1 mol of carbon dioxde gas has 1 mole pf carbon atoms,then [tex]5.4034\times 10^{-5} mol[/tex] will have ;
[tex]1\times 5.4034\times 10^{-5} mol=5.4034\times 10^{-5} mol[/tex] of carbon
Mass of [tex]5.4034\times 10^{-5} mol[/tex] of carbon ;
[tex]12 g/mol\times 5.4034\times 10^{-5} mol=0.0006484 g[/tex]
To calculate the ppm of oxygen in sea water, we use the equation:
[tex]\text{ppm}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6[/tex]
(Both the masses are in grams)
[tex]=\frac{0.0006484 g}{ 6.234 g}\times 10^6=104.01 ppm[/tex]
The ppm carbon in the seawater is 104.01.
