Answer:
The column height of air after the inversion is 7 cm.
Step-by-step explanation:
The initial pressure balance is given as
P_1+20 cm=76 cm of Hg
P_1=76-20 cm of Hg
P_1=56 cm of Hg
The initial volume of the air with cross sectional area as 12 cm2 and the length of air column as 12 is given as V_1=12 cm *1 =12 cm3
After the inversion
P_2=20 cm+76 cm of Hg
P_2=96 cm of Hg
The volume of the air after the inversion with cross sectional area as 1 cm2 and the length of air column as x is given as V_2=x *1 =x cm3
Now as temperature is constant and the cross sectional area is also constant so
[tex]P_1V_1=P_2V_2\\56\times 12=96\times x\\x=\dfrac{56\times 12}{96}\\x=7 cm[/tex]
So the column height of air after the inversion is 7 cm.
