Answer:
-4.5 m/s
Explanation:
Assuming steady and incompressible flow and uniform properties at each section
[tex]V_1A_1+V_2A_2+A_3V_3+Q_4=0[/tex]
Here V is velocity of flow and A is area, Q is flow rate out of the leak, subscript 1-4 represent different sections
At the surface, is negative hence the equation above will be
[tex]-V_1A_1+V_2A_2+A_3V_3+Q_4=0[/tex]
Making the subject of the formula then
[tex]V_2=\frac {V_1A_1-A_3V_3-Q_4}{A_2}[/tex]
Substituting the given values then
[tex]V_2=\frac {(5\times 0.2)-(12\times 0.15)-0.1}{0.2}=-4.5 m/s\\V_2=-4.5m/s[/tex]