Answer:
The molar mass of the gas is 44 g/mol
Explanation:
It is possible to solve this problem using Graham's law that says: Rates of effusion are inversely dependent on the square of the mass of each gas. That is:
[tex]\frac{r_1}{r_2} =\frac{\sqrt{M_2} }{\sqrt{M_1} }[/tex]
If rate of effusion of nitrogen is Xdistance / 48s and for the unknown gas is X distance / 60s and mass of nitrogen gas is 28g/mol (N₂):
[tex]\frac{X/48s}{X/60s} =\frac{\sqrt{M_2} }{\sqrt{28g/mol} }[/tex]
6,61 = √M₂
44g/mol = M₂
The molar mass of the gas is 44 g/mol
I hope it helps!