The potential difference between the bird's feet is 0.71 mV
Explanation:
Given-
Distance between the feet, x = 5 cm = 0.05 m
Diameter of the wire = 2 cm
Radius, r = 2/2 = 1 cm = 0.01 m
Current, I = 170 A
Potential difference, ΔV = ?
We know,
ΔV = IR
Where,
ΔV is the potential difference
I is the current
R is the resistance of the wire
And also
R = ρ L/ A
where,
ρ is the resistivity of aluminium wire (ρ = 2.65 X 10⁻⁸ Ωm)
L is the length
A is the area
Equating both the equations,
ΔV = I * ρL/A (The value of R is replaced in the first equation)
ΔV =
[tex]170 * \frac{(2.65 X 10^-^8) * 0.05}{\pi (0.01)^2} \\\\\frac{22.525 X 10^-^8}{0.000314} \\\\\frac{22.525 X 10^6}{314 X 10^8} \\\\0.0717 X 10^-^2\\\\7.17 X 10^-^4[/tex]
Therefore, the potential difference between the bird's feet is 0.71 mV
