Answer:
[tex]1060.41kg/m^3[/tex]
Explanation:
Bulk modulus is defined as the relative change in the volume of a body produced by a unit of compressive acting uniformly over its surface:
[tex]B=\rho _o \frac{\bigtriangleup P }{\bigtriangleup \rho}[/tex]
Hence the density of the seawater at a depth of 680atm is calculated as:-
[tex]\rho=\rho_o +\bigtriangleup \rho=\rho_o(1+\frac{\bigtriangleup P}{B})\\\\=1030 \times (1+ \frac{(680-1)\times10^5}{2.3\times 10^9})\\=1060.41kg/m^3[/tex]
