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A stock solution of Blue #1 has a concentration of 5.736 M. 3 mL of this solution is diluted with 8 mL water. What is the concentration of the resulting solution? Provide your response to 3 significant figures.

Respuesta :

Ifecosos

Answer:

1.56 M

Explanation:

This is a dilution process and so a dilution formula is suitably used as follows C1V1 = C2V2 where

C1 = concentration of the stock solution

V1 = volume of the stock solution

C2 = concentration of the resulting (dilute) solution and

V2 = the volume of the resulting (dilute) solution

C1V1 = C2V2 (Making C2 subject of the formula)

C2 = C1V1/V2

Given: C1 = 5.736 M; V1 = 3 Ml; V2 = (3+8) 11 Ml

C2 = 5.736 x 3 / 11

C2 = 1.56 M

Cricetus

The concentration of the resulting solution will be "1.56 M".

Dilution process:

The procedure of decreasing the concentration of such a particular solute through its solution has been known as dilution.

This same chemist could essentially add extra solvent to the mixture.

According to the question,

Stock solution's concentration, C₁ = 5.736 M

Stock solution's volume, V₁ = 3 mL

Resulting solution's volume, V₂ = 3 mL + 8 mL

                                                    = 11 mL

By using the dilution equation, we get

→ C₂ = [tex]\frac{C_1 V_1}{V_2}[/tex]

By substituting the above values,

       = [tex]\frac{5.736\times 3}{11}[/tex]

       = [tex]\frac{17.208}{11}[/tex]

       = [tex]1.56[/tex] M

Thus the above answer is right.

Find out more information about concentration here:

https://brainly.com/question/16343005

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