Answer:
Volume of nitrogen at STP = 1.92 L
Explanation:
Given data:
Initial volume of gas = 2.20 L
Initial temperature = 30°C (30+273 = 303 k)
Initial pressure = 735.43 mmHg (735.43/760 = 0.97 atm)
Final volume = ?
Final pressure = 1 atm
Final temperature = 273 K
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 0.97 atm × 2.20 L × 273 K / 303 K × 1 atm
V₂ = 582.58 atm .L. K / 303 K.atm
V₂ = 1.92 L
