Answer:
Q(0) = 0C, Q(1) = 264nC, Q(2) = 952C Q(3) = 2088nC, Q(4) = 3696C Q(5) = 5800nC
Explanation:
I = 4t³ + 200t² + 60t
But charge of an object =》 Q = IT
Charge of an object is the product of the current and the time in which the current passes through the membrane.
When t = 0
Q = 4(0)³ + 200(0)² + 60(0) = 0C
When t = 1
Q = 4(1)³ + 200(1)² + 60(1) = 264nC
When t = 2
Q = 4(2)³ + 200(2)² + 60(2) = 952nC
When t= 3
Q = 4(3)³ + 200(3)² + 60(3) = 2088nC
When t= 4
Q = 4(4)³ + 200(4)² + 60(4) = 3696nC
When t = 5
Q = 4(5)³ + 200(5)² + 60(5) = 5800nC
Answer:
The total charge that flows in the 5 second interval is 12,800 nA
Explanation:
To calculate the total charge, we need to find out the charge at each one second intervals, In order to do that, just plug in the value of t into the expression to find the value
I = 60(t) + 200(t²) + 4(t³)
at t = 0
I = 60(0) + 200(0²) + 4(0³) = 0 nA
at t = 1
I = 60(1) + 200(1²) + 4(1³) = 264 nA
at t = 2
I = 60(2) + 200(2²) + 4(2³) = 952 nA
at t = 3
I = 60(3) + 200(3²) + 4(3³) = 2088 nA
at t = 4
I = 60(4) + 200(4²) + 4(4³) = 3696 nA
at t = 5
I = 60(5) + 200(5²) + 4(5³) = 5800 nA
Now add all of them together
0 + 264 + 952 + 2088 + 3696 + 5800 = 12,800 nA
Hope that answers the question. Have a great day!
