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A 0.041 kg bullet has a kinetic energy of 660 J.
What is the velocity of the bullet?
A. 180 m/s
B. 7 m/s
C. 14 m/s
D. 9 km/s

Respuesta :

Answer:

180m/s

Explanation:

Kinetic energy = ½ mv²

Where m= mass = 0.041kg

V= velocity =?

K. E = 660J

Therefore

K. E = ½ mv²

Input values given

660 = ½ × 0.041 × v²

Multiply both sides by 2

660×2  = 2 × 1/2 × 0.041 × v²

1320 = 0.041v²

Divide both sides by 0.041

1320/0.041 = 0.041v²/0.041

v² = 32195.12

Square root both sides

Sq rt v² = sq rt 32195.12

V = 179.5m/s

V is approximately = 180m/s

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