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A charge of 0.05 C moves a negative charge upward due to a 2 N force exerted by an electric field. What is the
magnitude and direction of the electric field?
0.03 N upward
0.03 N downward
40 N upward
40 N downward

Respuesta :

Answer:

Electric field at this position of charge is 40 N/C and upwards in the direction of force

Explanation:

As we know that the force on a charge due to electric field is given as

[tex]F = qE[/tex]

here we know that

F = 2 N

q = 0.05 C

now from above formula

[tex]2 = (0.05) E[/tex]

here we have

[tex]E = 40 N/C[/tex]

Answer:

40 n/c downward on edge! :)

Explanation:

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