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A 0.017-kg acorn falls from a position in an oak tree that is 18.5 meters above the ground.
Calculate the velocity of the acorn just before it reaches the ground (rounding your answer to the integer) and its kinetic energy when hitting the ground (rounding your answer to the nearest tenth).

Velocity _______________ m/s

Kinetic Energy _______________ J

Respuesta :

Answer:

Velocity= 19.05 m/s

Kinetic energy= 3.08 J

Explanation:

The corn possess potential energy. Feom law of conservation of energy, all the potential eneegy will be converted to kinetic energy, with negligible friction.

Potential energy, PE= kinetic energy, KE

Potential energy is given by mgh while kinetic energy is given by [tex]0.5mv^{2}[/tex]

Equating

[tex]mgh=0.5mv^{2}[/tex]

Making v the subject of the formula then

[tex]v=\sqrt {2gh}[/tex]

Substituting 9.81 m/s2 for g and 18.5 m for h then the velocity will be

[tex]v=\sqrt {2\times 9.81\times 18.5}=19.0517715711689\ m/s\\v\approx 19.05\ m/s[/tex]

To get the kinetic eneegy, since PE=KE AND KE is

[tex]KE=0.5mv^{2}[/tex]

Substituting v with 19.05 and m with 0.017 kg we have

[tex]0.5\times 0.017\times 19.05^{2}=3.08467125/ J\approx 3.08 J[/tex]

This can also be achieved by mgh since PE=KE hence 0.17*9.81*18.5=3.085245 J and the results are slightly different due to small energy losses and rounding off of values.