Answer:
acceleration=2.0833 m/s^2
Tension in rope A=104.167 N
Tension in rope B=62.5 N
Explanation
mass of sleds are 10,20 and 30 Kg respectively.
Total mass =60 kg
F=ma
a=f/m
f=125 N
a=125/60
a=2.0833 m/s^2
Now using equation of equilibrium
F-Ta=ma*a
Ta=F-ma*a
Ta=125-(10*2.0833)
Ta=104.167 N
Tb=mc*a
Tb=30*2.0833
Tb=62.5 N
Question
The question is incomplete. The figure 5.48 was not attached to your question and the mass of the sleds is needed to answer the question. Below is the mass of the three sleds and the answer to the question.
10.0kg, 20.0kg and 30.0 kg
Answer:
Explanation:
Given data;
Force = 125N
mass of the three sleds =30.0 kg, 20.0 kg and 10.0 kg
(a) acceleration:
The acceleration is calculated using the formula;
F = ma
where F is the force, m is the mass and a is the acceleration
making acceleration subject formula, we have
a = F/m
but total mass = 30+20+10 = 60kg
a = 125/60
(b) Tension in Rope A:
by using the equilibrum formula,
F-Tₐ=mₐ*a
Where Tₐ is tension in rope A and mₐ is mass of rope A
making Tₐ subject, we have
Substituting, we have
Tₐ = 125 - 10*2.083
= 125 - 20.83
(b) Tension in Rope B:
Tb=30*2.083
Tb=62.49 N
