An instructor was interested in seeing if there was a difference in the average amount of time that men and women anticipate studying for an introduction to statistics course in the summer. a group of men and women were randomly selected from the university of florida. the minitab results are below. what is the best interpretation of the results below? difference = mu (f) - mu (m) t-test of difference = 0 (vs not =): t-value = 0.23 p-value = 0.817 df = 46

A. With a p-value of 0.817, that there is no statistically significant evidence of a difference in average anticipated amount of time studying between the men and women.

Step-by-step explanation:

The p-value is greater than the confidence level of 0.05, so we accept the null hypothesis (difference = 0). Therefore, we conclude there is no statistically significant difference between the average times for men and women.

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joaobezerra joaobezerra · Answer 2 · 2021-11-20T21:27:35+01:00

Using the t-distribution, it is found that since the p-value is of 0.817 > 0.05, it can be concluded that there is no difference in the average amount of time that men and women anticipate studying for an introduction to statistics course in the summer.

At the null hypothesis, it is tested if there is not a difference, that is:

[tex]H_0: \mu_f - \mu_m = 0[/tex]

At the alternative hypothesis, it is tested if there is a difference, that is:

[tex]H_1: \mu_f - \mu_m \neq 0[/tex]

The significance level is 0.05.
The p-value is of 0.817.

Since the p-value is of 0.817 > 0.05, it can be concluded that there is no difference in the average amount of time that men and women anticipate studying for an introduction to statistics course in the summer.

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