Answer: The number of moles of gas present are 0.390 moles
Explanation:
To calculate the number of moles of gas, we use the equation given by ideal gas which follows:
[tex]PV=nRT[/tex]
where,
P = pressure of the gas = 0.868 atm
V = Volume of the gas = 11 L
T = Temperature of the gas = [tex]25^oC=[25+273]K=298K[/tex]
R = Gas constant = [tex]0.0821\text{ L. atm }mol^{-1}K^{-1}[/tex]
n = number of moles of gas = ?
Putting values in above equation, we get:
[tex]0.868atm\times 11L=n\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 298K\\\\n=\frac{0.868\times 11}{0.0821\times 298}=0.390mol[/tex]
Hence, the number of moles of gas present are 0.390 moles
