please help

Write the standard equation of a circle that passes through (−4, 0) with center (−1, −4).

(x + 4)2 + y2 = 25

(x + 1)2 + (y + 4)2 = 25

(x – 4)2 + y2 = 25

(x – 1)2 + (y – 4)2 = 25

Respuesta :

Answer:

The answer to your question is     (x  + 1)² + (y + 4)² = 25

Step-by-step explanation:

Data

Point = (-4, 0)

Center = (-1, -4)

Process

1.- Calculate the length of the radius

dCP = [tex]\sqrt{(x2 - x1)^{2} + (y2 - y1)^{2}}[/tex]

-Substitution

dCP = [tex]\sqrt{(-1 + 4)^{2} + (-4 + 0)^{2}}[/tex]

-Simplification

dCP = [tex]\sqrt{3^{2}+ 4^{2}}[/tex]

dCP = [tex]\sqrt{9 + 16}[/tex]

dCP = [tex]\sqrt{25}[/tex]

dCP = 5

2.- Substitute the values in the equation of a circle

                  (x - h)² + (y - k)² = r²

                  (x  + 1)² + (y + 4)² = 5²

                  (x  + 1)² + (y + 4)² = 25