Answer:
The number of animals of the species will be left in 2025 = 2519 animals
Step-by-step explanation:
The number of animals of a certain species in 1980 = 20000
The rate of decrease each year = 4.5 %
The number of animals left in 2025 = ???
The number of years between 1980 and 2025 = 45
By formula of depreciation,
[tex]Pn = P (1 - R/100) ^ T[/tex]
where Pn is the population in 2025
P is the population in 1980
R is the rate of decrease in population
Substituting the values in the equation, we get
[tex]Pn = 20000 (1 - 4.5/100) ^ {45}[/tex]
= [tex]20000 (0.955) ^ {45}[/tex]
=2518.7 = 2519 species.
