Respuesta :

Eduard22sly

Answer:

255.51cm3

Explanation:

Data obtained from the question include:

V1 (initial volume) =?

T1 (initial temperature) = 50°C = 50 + 273 = 323K

T2 (final temperature) = - 5°C = - 5 + 237 = 268K

V2 (final volume) = 212cm3

Using the Charles' law equation V1/T1 = V2/T2, the initial volume of the gas can be obtained as follow:

V1/T1 = V2/T2

V1/323 = 212/268

Cross multiply to express in linear form

V1 x 268 = 323 x 212

Divide both side by 268

V1 = (323 x 212)/268

V1 = 255.51cm3

Therefore, the initial volume of the gas is 255.51cm3

Answer:

Explanation:

To get the initial volume of the hydrogen in cm³, we apply the equation generated from Charles' law.

V1/T1=V2/T2

Where;

V1=initial volume of gas

T1=initial temperature of gas

V2=final volume of gas

T2=final temperature of gas

We make V1 subject of formula

V1=(V2×T1)/T2

Given;

V2=212cm³

T1=50°C=(50+273)K=323K

T2=-5.0°C=(-5.0+273)K=268K

V1=(212×323)/268

V1=255.5cm³

Therefore, the initial volume of the hydrogen was 255.5cm³

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