Answer: the maximum number of toy they can get is 16.
Step-by-step explanation:
If chloe has $30 and her friend has 1/3 of the amount, it means that the amount that her friend has is
1/3 × 30 = $10
The total amount that they have is
30 + 10 = $40
They need a bag of food that cost $7 and they also want toys that are $2 each.
Let x represent the number of toys that they want to get. The total cost of a bag of food and x toys is
7 + 2x
Since they have $40, then the expression would be
7 + 2x ≤ 40
2x ≤ 40 - 7
2x ≤ 33
x ≤ 33/2
x ≤ 16.5
Since the number of toys cannot be a fraction, then the maximum number of toy they can get is 16
We want to see what is the maximum number of toys that Chloe and Charlie can get a maximum of 16 toys.
So we know that they need a bag of dog food that costs $7 and some toys, such that each toy costs $2.
So, if they buy x toys, the cost will be:
C(x) = $7 + $2*x
Now, we know that Chloe has $30 and charlie has 1/3 of that, so Charlie has:
(1/3)*$30 = $10
Then in total they have $30 + $10 = $40, so the maximum cost can be $40, then we must solve:
C(x) = $40 = $7 + $2*x
$40 - $7 = $2*x
$33 = $2*x
$33/$2 = 16.5 = x
Rounding down (because they can't buy a 0.5 of a toy) we see that the maximum number of toys that they can buy is 16.
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