Answer:
[tex]a=p=\frac{1}{6}\\\\b. \ p=\frac{1}{12}\\\\c.\ 1H,1T,2H,2T,3H,3T,4H,4T,5H,5T,6H,6T[/tex]
Step-by-step explanation:
a. A fair dice has 6 sides with unique identities.
-The sample space of one throw is 6 and each face has an equal chance of showing up.
-The probability of a 6 is calculated as:
[tex]p(six)=\frac{1}{6}\\\\or \ =0.1667[/tex]
Hence, the probability of a 6 is [tex]\frac{1}{6}[/tex]
b.A fair die has 6 unique faces.
-Two throws will have a sample space of 12.
-Each face has an equal probability of appearing twice.
-The probability of a 6 on both throws is:
[tex]P(six)=2\times \frac{1}{6}\\\\=\frac{1}{12}[/tex]
c. A coin has 2 sides(head, tail) and a die has 6 sides.
-The total sample space for the simultaneous throw of a coin and die is 12.
-The resultant sample space is :
[tex]1H,1T,2H,2T,3H,3T,4H,4T,5H,5T,6H,6T[/tex]