contestada

A mass M is attached to an ideal massless spring. When the system is set in motion, it oscillates with a frequency f. What is the new oscillation frequency if the mass is doubled to 2M? g

Respuesta :

opudodennis

Answer:

[tex]\frac {f_i}{\sqrt 2}[/tex]

Explanation:

Frequency is given by [tex]\frac {1}{2\pi}\sqrt{{\frac {k}{m}}[/tex]

Let the initial frequency be denoted by [tex]f_i[/tex]

[tex]f_i=\frac {1}{2\pi}\sqrt{{\frac {k}{M}}[/tex]

When M is 2M then

[tex]f_f=\frac {1}{2\pi}\sqrt{{\frac {k}{2M}}=\frac {f_i}{\sqrt 2}[/tex]

Therefore, the final frequency is

[tex]\frac {f_i}{\sqrt 2}[/tex]