Answer:
130, 131, 132, 133
Step-by-step explanation:
Let the first page numbe be x, the next x+1, x+2, x+3
The sum of the first two will be x+x+1=2x+1
The sum of the last two will be x+2+x+3=2x+5
Product will be (2x+1)(2x+5)
Since the product equals 69165
(2x+1)(2x+5)=69165
[tex]4x^{2}+10x+2x+5=69165\\4x^{2}+12x+5=69165\\4x^{2}+12x-69160=0\\x^{2}+3x17290\\(x-130)((x+130)=0\\x=130, -133[/tex]
Therefore, x=130
Next pages are 131, 132, 133
