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A person is diving in a lake in the depth of h = 15 m. The density of the water is rho = 1.0 x103 kg/m3. The pressure of the atmosphere is P0 = 1.0 x 105 Pa. The surface area of the top of the person's head is A = 0.036 m2.

(a) Express the absolute pressure at the depth of h , Po, Q in terms of Poe, and h

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rafaleo84

Answer:

Pabs = 247150 [Pa]

Explanation:

The pressure in the depth h can be calculated by the following expression.

Pabs = Po + (rho * g * h)

Where:

g = gravity = 9.81[m/s^2]

rho = density = 1000 [kg/m^3]

h = depth = 15 [m]

Po = 100000 [Pa]

Pabs = 100000 + (1000*9.81*15)

Pabs = 247150 [Pa]

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