Answer : The half-life of the reaction in seconds is, 244
Explanation :
The expression used for zero order reaction is:
[tex]t_{1/2}=\frac{[A_o]}{2k}[/tex]
where,
[tex]t_{1/2}[/tex] = half-life of the reaction = ?
[tex][A_o][/tex] = initial concentration = 5.90 M
k = rate constant = 0.725 M/min
Now put all the given values in the above formula, we get:
[tex]t_{1/2}=\frac{5.90}{2\times 0.725}[/tex]
[tex]t_{1/2}=4.069min=244.14s\approx 244s[/tex]
conversion used : (1 min = 60 s)
Thus, the half-life of the reaction in seconds is, 244
