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Compute the distance between (7,-4,9) and (x,y,z).
a. (7 + x)2 + (-4 + y)2 + (9 + 2)2
b. (7 - x)2 + (-4 - y)2 + (9 - 2)2
C.
d.
7- x) + (-4-y) + (9 -23
(7+ x)2 + (-4+ y)2 + (9+ 2)2

Respuesta :

danielmaduroh

Answer:

Option b:

[tex]\boxed{ d=\sqrt{(7-x)^2+(-4-y)^2+(9-z)^2}}[/tex]

Explanation:

Let two points be:

[tex]P_{1}(x_{1},y_{1},z_{1}) \\ \\ P_{2}(x_{2},y_{2},z_{2})[/tex]

The distance formula is defined as:

[tex]d=\sqrt{(x_{1}-x_{2})^2+(y_{1}-y_{2})^2+(z_{1}-z_{2})^2}[/tex]

Therefore, if we define:

[tex]P_{1}(7,-4,9) \ and \ P_{2}(x,y,z) \\ \\ \\ Then: \\ \\ d=\sqrt{(7-x)^2+(-4-y)^2+(9-z)^2}[/tex]

Finally, correct option is b

Answer:

The Answer is correct, he just has the wrong letter.

Step-by-step explanation:

The correct answer is C

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