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How many atoms of phosphorus are in 2.30 mol of copper(II) phosphate? I'm having trouble figuring out the steps. I do know Avogadro's number is needed! 6.022x10^23

Respuesta :

taskmasters
Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. The calculation is as follows:

2.30 mol Cu3(PO4)2 ( 2 mol P / 1 mol Cu3(PO4)2) ( 6.022 x 10^23 atoms / mole) = 2.77 x 10^24 atoms P
Ishankahps

Answer is 2.77012 x 10²⁴

Explanation;

The formula of copper(II) phosphate is Cu₃(PO₄)₂. Hence, 1 Cu₃(PO₄)₂ has 2 P atoms. The stoichiometric ratio between Cu₃(PO₄)₂ and P atom is 1 : 2.

Hence,

moles of P atoms = moles of Cu₃(PO₄)₂ x 2

= 2.30 mol x 2 = 4.60 mol

According to the Avogadro's constant, 1 mole has 6.022 x 10²³ particles.

Hence, number of P atoms = Avogadro's constant x number of moles

= 6.022 x 10²³ mol⁻¹ x 4.60 mol

= 2.77012 x 10²⁴


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