Answer:
Explanation:
Given that,
Wave equation is
Ey = 375•Cos(kx — 2.2 × 10¹⁴t)
Generally,
The wave equation is written as
Ey = Eo•Cos(kx-wt)
Where
K is wave number
ω is the angular frequency
So, comparing this to the the given wave equation, we found out that,
ω = 2.2 × 10¹⁴ rad / s
Then,
ω = 2πf
f = ω / 2π
From the relationship between wavelength and speed
v = fλ
Substitute for f
v = λ × ω / 2π
In electromagnetic we are dealing with speed of light , then, v = c
c = λ × ω / 2π
c is speed of light in vacuum and it's value is
c = 3 × 10^8 m/s
Make wavelength subject of the formula
λ = 2π × c / ω
λ = 2π × 3 × 10^8 / 2.2 × 10¹⁴
λ = 8.57 × 10^-6 m
λ = 8.57 μm
The wave length is 8.57 μm
