Answer:
Minimum of 12 rolls of wrapping paper
Step-by-step explanation:
Before we can calculate the minimum amount of rolls of wrapping paper that Petrich needs for all four presents, we need to know the volume of each box wrapped.
For box with dimension
- 8.5" × 14.5" × 1.5"
Volume = 185.875in³
For box with dimension
- 9.5" × 14.5" × 2"
Volume = 275.5in³
For box with dimension
- 11" × 16" × 3"
Volume = 528in³
For box with dimension
- 15.5" × 12" × 4"
Volume = 744in³
If a standard roll of wrapping paper is 30" long with nine feet (three yards) of paper
Number of rolls needed for all four boxes = Total volume of all boxes/standard roll
Total volume of boxes = 185.87+275.5+528+744
= 1733.37in³
Dimension of standard roll = 30in+9feet
Since 1foot = 12inches
9feet = 9×12 = 108inches
Dimension of standard roll = 30+108
= 138inches
Number of rolls needed for all four boxes = 1733.37/138
= 12.56
Approximately 12 rolls of wrapping paper is needed by Petrich for all the four boxes.
