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An isosceles triangle has area of 110 ft. If the base is 14 ft, what is the length of each leg? Round your
answer to the nearest tenth.
Time Running
Artemot du May 22
1 Hour, 9 Minutes
21 ft
14.8 ft
17.2 ft
442.9 ft

Respuesta :

aryasus30

Answer:

h=15,7 ft

l1=19.8

l2=l1=19.8

Step-by-step explanation:

A=(b×h)/2

110=x×14/2

x×14=220

x=220/14=15,7

h=15.7 ft

l=rad(144+246.7)=19,8

l1=l2=19,8

mailpjpatel

Answer:

Step-by-step explanation:

Area = 1/2*b*h

110 = 1/2 * 14 * h

15.714 = h

Pythagoren th

c^2 = a^2 + b^2

c^2 = 7^2 + (15.714)^2

c^2 = 49 + 246.93

c^2 = 295.93

c = 17.2

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