Answer:
see below.
Step-by-step explanation:
f(x) = 5/x
1.a) f(x) is not linear, it should be a hyperbola. Since there are asymptotes , a center point, Foci, etc. but it is not the usual hyperbola s in
y^2/b^2 - x^2/a^2 = 1
b.) asymptotes: x = 0 and y = 0
Vertical Asymptote : x = 0
Horizontal Asymptote: y =0
c.) Domain: (-infinity, 0) U (0, + infinity)
Range : (- infinity, 0 ) U (0, + infinity)
d.) End behavior of f(x) is y = 0 as x gets very large f(x) approaches ZERO
e.) f(x) exists in quadrants 1 and 3 only .
