Answer:
see below
Step-by-step explanation:
Interchange x and y, then solve for y.
[tex](x-4)^2-\dfrac{2}{3}=6y-12\qquad\text{given}\\\\(y-4)^2=6x-\dfrac{36-2}{3}\qquad\text{swap x,y; add 2/3}\\\\y-4=\pm\sqrt{6x-\dfrac{34}{3}}\\\\\boxed{y=4\pm\sqrt{6x-\dfrac{34}{3}}}[/tex]