Step-by-step explanation:
Step 1: Make a system of equation
The sum of two numbers is 41
x + y = 41
The larger number is one less than twice the smaller number.
x = 2y - 1
Step 2: Substitute x from the second equation into the first
[tex]x + y = 41[/tex]
[tex](2y - 1) + y = 41[/tex]
[tex]3y - 1+ 1 = 41 + 1[/tex]
[tex]3y/3 = 42 / 3[/tex]
[tex]y = 14[/tex]
Step 3: Substitute y into the second equation
[tex]x = 2y - 1[/tex]
[tex]x = 2(14) - 1[/tex]
[tex]x = 28 - 1[/tex]
[tex]x = 27[/tex]
Answer: [tex]x = 27, y = 14[/tex]
