nsw2003
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Line segment AB was dilated to create line segment A'B' using the dilation rule DQ,0.15.


What is x, the distance between points A and A'?

2.4 units

4.8 units

13.6 units

14.4 units

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Line segment AB was dilated to create line segment AB using the dilation rule DQ015What is x the distance between points A and A24 units48 units136 units144 uni class=

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Answer:

13.6

Step-by-step explanation:

The measure of the segment AQ is related to the measure of the segment A'Q by the dilation factor as follows:

dilation factor = A'Q/AQ

AQ = A'Q/dilation factor

Replacing with data:

AQ = 2.4/0.15 = 16

Then, the distance between points A and A' is

x = 16 - 2.4 = 13.6

abidemiokin

The  distance between points A and A' is 13.6 units

Dilation of coordinates

Dilation is a way of changing the position of an image on an xy-plane.

The measure of the segment AQ is related to the measure of the segment A'Q by the dilation factor. Hence'

scale factor = A'Q'/AQ

Given the following

A'Q' = 2.4

Scale factor = 0.15

Substitute

AQ = 2.4/0.15

AQ = 16

x = 16 - 2.4

x = 13.6

Hence the  distance between points A and A' is 13.6 units

Learn more on dilation here: https://brainly.com/question/10253650

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