Answer:
0-9(n-1)
Step-by-step explanation:
We can tell the first term of the sequence is 0 and the common difference is -9. So the explicit formula would be h(n)=0-9(n-1)
The explicit formula for h(n) comes to be h(n)=9-9n.
An arithmetic progression is a list of numbers where the difference between consecutive terms is always constant.
[tex]h(n)=h(n-1)-9[/tex]
[tex]h(n)-h(n-1)=-9[/tex]
So the common difference of the arithmetic progression will be -9.
[tex]h(1)=0[/tex] means the first term of the AP is 0.
We know that [tex]n^{th}[/tex] term of an AP is given by:
[tex]h(n)=a+(n-1)d[/tex]
Where a is the first term and d is a common difference.
Fo the given series [tex]a=0[/tex] and [tex]d=-9[/tex]
So, [tex]h(n)=0+(n-1)(-9)[/tex]
[tex]h(n)=9-9n[/tex]
So, the explicit formula for h(n) is [tex]h(n)=9-9n[/tex]
Hence, the explicit formula for h(n) comes to be [tex]h(n)=9-9n[/tex].
To get more about arithmetic progressions visit:
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