Answer:
[tex]\large \boxed{36\sqrt{2}\text{ units}}[/tex]
Step-by-step explanation:
Assume ∆DEF looks like the one below.
We can use Pythagoras' Theorem to find the hypotenuse f.
[tex]\begin{array}{rcl}d^{2} + e^{2} & = & f^{2}\\36^{2} + 36^{2} & = & f^{2}\\f^{2} & = & 2 \times 36^{2}\\f & = & \sqrt{2 \times 36^{2}}\\& = & 36\sqrt{2}\\\end{array}\\\text{The length of the hypotenuse is $\large \boxed{\mathbf{36\sqrt{2}}\textbf{ units}}$}[/tex]
