Answer:
1L
Explanation:
Data obtained from the question include:
Initial volume (V1) = 25L
Initial temperature (T1) = 12750°C
Final temperature (T2) = 250°C
Final volume (V2) =..?
Next we shall convert from celsius to Kelvin temperature. This is illustrated below:
T(K) = T(°C) + 273
Initial temperature (T1) = 12750°C
Initial temperature (T1) = 12750°C + 273 = 13023K
Final temperature (T2) = 250°C
Final temperature (T2) = 250°C + 273 = 523K
Finally, we can obtain the new volume of the gas by using Charles' law equation as shown below:
V1/T1 = V2/T2
25/13023 = V2/523
Cross multiply to express in linear form
13023 x V2 = 25 x 523
Divide both side by 13023
V2 = 25 x 523 / 13023
V2 = 1L
Therefore, the new volume of the gas is 1L.
The volume of this gas after it cools to 250°C is equal to 0.490 Liter.
Given the following data:
To determine the volume of this gas after it cools to 250°C, we would apply Charles's law:
Mathematically, Charles law is given by the formula;
[tex]\frac{V}{T} =k\\\\\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]
Where;
Substituting the given parameters into the formula, we have;
[tex]\frac{25}{12750} = \frac{V_2}{250} \\\\25 \times 250 = 12750V_2\\\\6250 = 12750V_2\\\\V_2 = \frac{6250}{12750}[/tex]
Final volume = 0.490 Liter.
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