Respuesta :
Answer : The mass of copper required is, 0.768 g
Explanation : Given,
Mass of silver nitrate = 4 g
Molar mass of silver nitrate = 170 g/mole
Molar mass of copper = 64 g/mole
First we have to calculate the moles of [tex]AgNO_3[/tex].
[tex]\text{Moles of }AgNO_3=\frac{\text{Mass of }AgNO_3}{\text{Molar mass of }AgNO_3}=\frac{4g}{170g/mole}=0.024moles[/tex]
Now we have to calculate the moles of Cu.
The balanced chemical reaction is,
[tex]Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag[/tex]
From the balanced reaction we conclude that
As, 2 moles of [tex]AgNO_3[/tex] react with 1 mole of [tex]Cu[/tex]
So, 0.024 moles of [tex]AgNO_3[/tex] react with [tex]\frac{1}{2}\times 0.024=0.012[/tex] moles of [tex]Cu[/tex]
Now we have to calculate the mass of Cu.
[tex]\text{Mass of }Cu=\text{Moles of }Cu\times \text{Molar mass of }Cu[/tex]
[tex]\text{Mass of }Cu=(0.012mole)\times (64g/mole)=0.768g[/tex]
Therefore, the mass of copper required is, 0.768 g
Mass of copper is required to completely replace silver = 0,7493 grams
Further explanation
Stokiometry in Chemistry learns about chemical reactions mainly emphasizing quantitative, such as calculation of volume, mass, number, which is related to the number of ions, molecules, elements, etc.
In stoichiometry therein includes
• 1. a relative atomic mass is a measurement of the mass of an atom relative to the mass of 1 carbon-12 atom
• 2. The relative molecular mass is the sum of the mass of the entire atomic mass making up the molecule or is the sum of the relative atomic masses that make up the molecule
• 3. Mol is a unit of the number of particles where 1 mole is the number of particles contained in a substance which is equal to many atoms in 12 gr C-12
1 mol = 6.0210²³ particles
- 4. The volume per mole of gas is called the molar volume
V = n × Vm
V = volume of gas, liter
n = mole
Vm = molar volume (liters / mol)
Molar volume depends on conditions:
- 1. Standard state
Conditions at T 0 ° C and P 1 atm
VM is 22.4 liters/mol.
- 2 Room Conditions
Conditions at T 25 ° C and P 1 atm Vm in this condition = 24.4 liters / mol
While the number of moles can also be obtained by dividing the mass (in grams) by the relative mass of the element (Ar) or the relative molecular mass (Mr)
mole = gram / (Ar / Mr)
Reaction that happened
Cu(s) + 2 AgNO₃ → Cu(NO₃)₂ + 2Ag.
known 4 grams of silver nitrate AgNO ₃
From the reaction, equation shows the reaction coefficients of Cu and AgNO₃ = 1: 2 so that the mole ratio of both is also 1: 2
We specify the mole of AgNO₃
relative molecular mass AgNO₃ = 170
so mole AgNO3 = 4/170
= 0.0235
so that
mass [tex]Cu[/tex] = 0.0235./2 . relative atom mass
= 0,0118 . 63.5
= 0,7493 grams
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Keywords: Stokiometry, mole, grams, AgNO₃