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Xavier is roller skating at 14 km/h and tosses a set of keys on the ground at 8 km/h. The speed of the keys relative to the ground is km/h.

Respuesta :

carlosego

The speed of the keys with respect to the ground is given by:

[tex] V_{k-g} = V_{k-s} + V_{s-g} [/tex]

Where,

Vk-s: Speed of the keys with respect to the skater

Vs-g: Speed of the skater compared to the ground

Substituting values in the equation we have:

[tex] V_{k-g} = 8 + 14
[/tex]

[tex] V_{k-g} = 22 \frac{Km}{h}
[/tex]

Answer:

The speed of the keys relative to the ground is 22 km / h.

onyebuchinnaji

The speed of the keys relative to the ground is determined as 22 km/h.

Velocity of the key relative to the ground

The speed of the key relative to the ground is calculated as follows;
Vk/g = Va + Vb

where;

  • Va is speed of Xavier
  • Vb is speed of the key

Vk/g = 14 km/h + 8 km/h

Vk/g = 22 km/h

Thus, the speed of the keys relative to the ground is determined as 22 km/h.

Learn more about relative velocity here: https://brainly.com/question/17228388
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