Answer:
2.41065 grams
Explanation:
Here we have to apply molarity, particularly in reference to the equation molarity = moles of solute / volume. I would like to rewrite this formula, but with respect to the units - grams = moles / Liters,
We can use molarity to determine the number of moles. After doing so, we can determine the mass of the solute with respect to the formula moles = mass / molar mass. The molar mass of NaCl is 58.44 grams.
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275 mL = 0.275 L,
Number of Moles of NaCl = 0.150 * 0.275 = 0.04125 moles,
Mass = 0.04125 * 58.44 = 2.41065 grams,
Solution - Mass of NaCl = 2.41065 grams
Hope that helps!
Answer:
2.41g
Explanation:
Data obtained from the question include the following:
Molarity of NaCl = 0.150M
Volume = 275mL
Mass of NaCl =..?
Next, we shall determine the number of mole of NaCl in the solution. This is illustrated below:
Molarity of a solution is simply defined as the mole of solute per unit litre of the solution. Mathematically, the molarity is expressed as:
Molarity = mole /Volume
Molarity = 0.150M
Volume = 275mL = 275/1000 = 0.275L
Mole =..?
Molarity = mole /Volume
0.150 = mole /0.275
Cross multiply
Mole = 0.15 x 0.275
Mole = 0.04125 mole
Therefore, the number of mole of solute, NaCl in the solution is 0.04125 mole.
Finally, we shall convert 0.04125 mole of NaCl to farms. This is illustrated below:
Molar mass of NaCl =23 + 35.5 = 58.5g/mol
Mole of NaCl = 0.04125 mole
Mass of NaCl =..?
Mole = mass/molar mass
0.04125 = Mass /58.5
Cross multiply
Mass = 0.04125 x 58.5
Mass = 2.41g
Therefore, the mass of the solute, NaCl needed to prepare the solution is 2.41g
